(a + 3)( b + 2)
ab + 4 + a + 4b factors to (a + 4)(b + 1)
(a + b)(b - 2c)
(b - x)(ab - xy)
e a cd
0
That factors to (b + 3)(a + c)
The GCF is a.
a(b+3)+b(b+3)
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
The factors of 3a are 3 and a. The factors of 6c are 6 and c. The factors of ab are a and b.
(a - 2)(b + 3)
ab-2ac+b^2-2bc
You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )
(a + b)(b + c)
(a + 3)( b + 2)
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)