a(3+b)+c(3+b)
* * * * *
This is easy to finish:
. . . = (a + c)(3 + b).
(a + 3)( b + 2)
ab + 4 + a + 4b factors to (a + 4)(b + 1)
(a + b)(b - 2c)
(b - x)(ab - xy)
e a cd
0
That factors to (b + 3)(a + c)
The GCF is a.
a(b+3)+b(b+3)
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
The factors of 3a are 3 and a. The factors of 6c are 6 and c. The factors of ab are a and b.
To solve the equation ( ab + 3c^2d = 0 ) for ( b ), first isolate the term involving ( b ) by subtracting ( 3c^2d ) from both sides, resulting in ( ab = -3c^2d ). Then, divide both sides by ( a ) (assuming ( a \neq 0 )) to get ( b = \frac{-3c^2d}{a} ).
(a - 2)(b + 3)
ab-2ac+b^2-2bc
You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )
(a + 3)( b + 2)
(a + b)(b + c)