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What is the GCF of ab and bc?
The GCF is b.
What is greatest common factor of ab-bc?
The GCF is b.
What is the LCM of ab and bc?
The least common multiple (LCM) of two numbers is the smallest number that is a multiple of both numbers. In this case, the LCM of ab and bc would be the product of the two numbers divided by their greatest common divisor (GCD), which is b. Therefore, the LCM of ab and bc is abc.
What is the greatest common factor of the products ab ac and bc if b is a factor of c?
The answer depends on whether or not a is a factor of c.
How do you factor ax-xb-ay plus yb?
Recall distributivity a(b + c) = ab + ac = (b + c)a and associativity (ab)c = a(bc) (a + b) + c = a + (b + c) as well as commutativity ab = ba a + b = b + a we are gonna need those. See for yourself when I applied each to learn the trick: ax - bx - ay + yb = (ax - bx) + (-ay + yb) = x(a - b) + -y(a - b) = (x - y)(a - b)
Can you factor this ab plus 3a-bc-3c?
0
Factor 3a plus ab plus 3c plus bc?
a(3+b)+c(3+b) * * * * * This is easy to finish: . . . = (a + c)(3 + b).
If ab plus bc equals ac then ac equals ab plus bc?
yes because ab plus bc is ac
Ab plus bc equals bc plus ab what property is this?
Commutativity.
Use Boolean algebra to simplify the logic function and realize the given function and minimized function using discrete gates. f equals ab c plus abc plus ac plus bc plus abC.?
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
How do you factor ab plus bc plus b2 plus ac?
(a + b)(b + c)
What is 15ac plus 20bc plus 6ad plus 8bd?
15 ac + 20 bc + 6 ad + 8 bd =3a (5c + 2d) + 4b (5c + 2d) =(3a + 4b) (5c + 2d)
If point C is between points A and B then AC plus CB .?
The real answer is Bc . Hate these @
What would a triangle look like if ab plus ac equals bc?
It would be a straight line of length bc
What does AB plus BC equals AC mean?
If point b is in between points a and c, then ab +bc= ac by the segment addition postulate...dont know if that was what you were looking for... but that is how i percieved that qustion.
If a over b equals c over d then is it possible that a plus b equals c plus d If not then give Mathematical Reason for that?
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
How do you prove that In a quadrilateral ABCD prove that AB plus BC plus CD plus DA 2( AC plus BD )?
You cannot prove it since it is not true for a general quadrilateral.
