10(3x + 1)
Make note that a term doesn't have to be a number. It can be the expression, like (3x - 6). In order to consider a term of the factorization of the term to be the factor, it must be prime. Therefore, we call each factor in a term "prime factor". Here is the example: 2x + 6 has a factor of 2. Then, we can factor out 2x + 6 to get 2(x + 3)
Notice that you have a common factor of 2 in both of these terms. So, you can factor out 2 out of each term and have a product: 2x + 2y = 2(x+y)
This statement is already nearly factored. The best we can do is pull out the 9 from each term:9x + 9y + 72 = 9(x + y + 8)
The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).
x2+10x-336
Common Apex
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
You don't, if you're only looking for real number results. If you are including imaginary numbers, x2+4 = (x+2i)*(x-2i).
The idea here is to multiply each term in the first polynomial by each term in the second polynomial.
You don't. That expression can not be factored. You can see that by observing that the only factors of the last term, 1 and 5, can not be added or subtracted from each other in any way that gives a sum of 10 (the coefficient of the middle term).
Find a number that evenly divides each term of the expression.
Well, honey, it looks like you've got yourself a simple linear expression there. Just pull out the common factor of 2 from both terms, and you're left with 2(x + 7). That's all there is to it, darling!