10(3x + 1)
Notice that you have a common factor of 2 in both of these terms. So, you can factor out 2 out of each term and have a product: 2x + 2y = 2(x+y)
Make note that a term doesn't have to be a number. It can be the expression, like (3x - 6). In order to consider a term of the factorization of the term to be the factor, it must be prime. Therefore, we call each factor in a term "prime factor". Here is the example: 2x + 6 has a factor of 2. Then, we can factor out 2x + 6 to get 2(x + 3)
This statement is already nearly factored. The best we can do is pull out the 9 from each term:9x + 9y + 72 = 9(x + y + 8)
To write each factor as a polynomial in descending order, first identify the terms of the polynomial and arrange them based on the degree of each term, starting with the highest degree. For example, if you have factors like (x^2 + 3x - 5) and (2x - 1), you would express each factor individually, ensuring that the term with the highest exponent comes first. Finally, combine all terms, maintaining the descending order for clarity and consistency.
The expression "18x plus 6" can be written mathematically as ( 18x + 6 ). This represents a linear equation where ( 18x ) is the term involving the variable ( x ), and ( 6 ) is a constant. If you want to simplify or factor it, you could express it as ( 6(3x + 1) ).
The product is(the product of the first term of each)plus(the product of the last term of each) plus(the product of the first term of the first and the last term of the second) plus(the product of the first term of the second and the last term of the first).
x2+10x-336
To factor a polynomial expression, you identify common factors among the terms and express the polynomial as a product of simpler polynomials. For example, consider the polynomial ( x^2 - 5x + 6 ); it factors into ( (x - 2)(x - 3) ). Each factor is written in descending order, starting with the highest degree term. The specific steps to factor will depend on the polynomial you are working with.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Common Apex
You don't, if you're only looking for real number results. If you are including imaginary numbers, x2+4 = (x+2i)*(x-2i).
You don't. That expression can not be factored. You can see that by observing that the only factors of the last term, 1 and 5, can not be added or subtracted from each other in any way that gives a sum of 10 (the coefficient of the middle term).