The 90th term of the arithmetic sequence is 461
This is the real question what is the 19th term in the arithmetic sequence 11,7,3,-1,...? _________________________________________________________ Looks like you just subtract 4 each time, as : 11,7,3,-1,-5,-9, ......
i dont get it
From any term after the first, subtract the preceding term.
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
It is a sequence of numbers which is called an arithmetic, or linear, sequence.
It is an arithmetic sequence if you can establish that the difference between any term in the sequence and the one before it has a constant value.
The nth term of an arithmetic sequence = a + [(n - 1) X d]
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
An arithmetic sequence
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.