This is the real question what is the 19th term in the arithmetic sequence 11,7,3,-1,...? _________________________________________________________ Looks like you just subtract 4 each time, as : 11,7,3,-1,-5,-9, ......
In this case, 22 would have the value of 11.
Any pair of numbers will always form an arithmetic sequence.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
U5 = a + 5n = 4 U7 = a + 7n = 10 Therefore 2n = 6 and so n = 3 and then a = 4 - 5n = 4 - 15 = -11 So Un = -11 + 3n and therefore, U10 = a + 10n = -11 + 10*3 = -11 + 30 = 19
In this case, 22 would have the value of 11.
It is an Arithmetic Progression with a constant difference of 11 and first term 15.
No, it is geometric, since each term is 1.025 times the previous. An example of an arithmetic sequence would be 10, 10.25, 10.50, 10.75, 11.
Any pair of numbers will always form an arithmetic sequence.
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
-1 deduct 3 each time
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
-161.
yes it is
35 minus 4 differences, ie 4 x 6 so first term is 11 and progression runs 11,17,23,29,35...
The next sequence for 98, 87, 76, 65 is 54 This is an arithmetic sequence with the first term being 98 and the common difference being -11 So the next term is 65+(-11) = 54