-4
"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
y
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
no the graph will be written in slope intercept form or y=mx+b
8
If the inequality is strict (< or >) then the boundary is not included. Otherwise (≤ or ≥), it is.
To accurately determine which inequality is shown in the graph, I would need to see the graph itself. However, if the graph displays a shaded region above a line, it typically represents a "greater than" inequality (e.g., y > mx + b), while shading below the line indicates a "less than" inequality (e.g., y < mx + b). Additionally, if the line is solid, it indicates that the points on the line are included in the solution (≥ or ≤), whereas a dashed line indicates they are not (>, <).
if you have y <= f(x), then graph the function y = f(x) with a solid line, then shade everything below that graph.
The inequality ( y < 8 ) is represented by a horizontal line at ( y = 8 ) with a dashed line, indicating that points on the line are not included in the solution. The area below this line represents the solution set, where all points have a ( y )-value less than 8. Therefore, any graph depicting this with the correct shading below the dashed line would accurately represent the inequality.
a graph