"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality. Rephrase and resubmit.
The shaded area of the graph of an inequality show the solution to the inequality. For example, if the area below y = x is shaded it is showing those ordered pairs which solve y < x.
no the graph will be written in slope intercept form or y=mx+b
-305y is not an equation (nor inequality) and so cannot represent a graph.
If the inequality is strict (< or >) then the boundary is not included. Otherwise (â‰¤ or â‰¥), it is.
The graph of an inequality is a region, not a line.
if you have y <= f(x), then graph the function y = f(x) with a solid line, then shade everything below that graph.
y -x - 2 is not an equation (nor an inequality) and so there is no way to graph it.
we should prevent inequality by
if you are looking at a graph the y intercept is when the graph crosses the y axis and the x intercept is when the graph crosses the x axis. if you have a formula... plug zero in for x to find the y intercept, and plug zero in for y to find the x intercept
graph the inequality 5x+2y<4
You can graph an equation or an inequality but you cannot graph an expression.
Acceleration=change in y graph/change in x graph
You find the slop and y-intersept
It can represent the graph of a strict inequality where the inequality is satisfied by the area on one side of the dashed line and not on the other. Points on the line do not satisfy the inequality.
find the constant of variation and the slope of the given line from the graph of y=2.5x
It is zero.
A bivariate linear inequality.
Instead of the answer being a curve, it is a region. For example, if y > x2 + 4, the answer is not the parabola y = x2 + 4. Instead it is the region above the parabola (as if the bowl were filled with something.)