"y - x + 1" is not an inequality. It is a simple expression. If you want something like "y - x + 1 > 0" that would be an inequality.
Rephrase and resubmit.
This compound inequality cannot be solved.
The way you state it, that is already the solution of some problem; perhaps of an inequality. There is nothing more you need to do, except perhaps graph it, if the problem asks for it.The way you state it, that is already the solution of some problem; perhaps of an inequality. There is nothing more you need to do, except perhaps graph it, if the problem asks for it.The way you state it, that is already the solution of some problem; perhaps of an inequality. There is nothing more you need to do, except perhaps graph it, if the problem asks for it.The way you state it, that is already the solution of some problem; perhaps of an inequality. There is nothing more you need to do, except perhaps graph it, if the problem asks for it.
(a) y = -3x + 1
3
x=1 and x=-7 are.
To determine the inequality represented by the graph, we need to analyze the lines and their slopes. If the line has a positive slope and the region above the line is shaded, it likely corresponds to option (1) or (3). If the line has a negative slope and the region below the line is shaded, it corresponds to option (2) or (4). Without seeing the graph, I can't specify which inequality it is, but you can use these clues to identify the correct option.
To graph the inequality ( y + 2 > -3(x + 1) ), first, rearrange it to isolate ( y ): ( y > -3x - 3 - 2 ), which simplifies to ( y > -3x - 5 ). This represents a straight line with a slope of -3 and a y-intercept of -5. Since the inequality is strict (greater than), you would draw a dashed line for ( y = -3x - 5 ) and shade the region above the line to indicate all the points that satisfy the inequality.
A graph that has 1 parabolla that has a minimum and 1 positive line.
You move the graph upwards by 2 units.
No it is not if you have a single inequality. It you had a single point as the solution, then it effect you would have an equality. If you have x> or equal to 1 and x< or equal to 1 then the graph is the single point 1. So it is possible with systems of inequalities.
Neither x-1 nor x4 is an equation or an inequality. There is, therefore, nothing to graph anything.
It would be easier to answer the question if there were any graphs to be seen. But since there are none, there is no proper answer either.
y=x+1 there for answer is 2
x>5
the inequality& graph of 0<n - 1 + 6 the solution
It is the inequality: N + 2 <= 1.
This compound inequality cannot be solved.