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Q: Find the nth term of the sequence: 3, 11, 21, 33, 47, 63, 81?

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The nth term of the sequence is 2n + 1.

The nth term in this sequence is 4n + 3.

11+6n

One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1

The nth term is 4n-1 and so the next term will be 19

The nth term of the sequence is (n + 1)2 + 2.

It works out as -5 for each consecutive term

The 'n'th term is [ 4 - 3n ].

The 'n'th term is [ 4 - 3n ].

The 'n'th term is [ 4 - 3n ].

The nth term is: 3n+2 and so the next number will be 20

3 11

Un = 29 - 9n

i relly dont know tony

Double it minus the previous number.

The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.

5, 11, 17, 23, 29

11

The nth term is 2n+5 and so the next number is 17

First look for the difference between the terms, for example the sequence: 5, 8, 11, 14... has a difference of 3. This means the sequence follows the 3 times table - i.e. 3n Now since we need the first term to be 5 we add 2 to our rule to make it work. So the nth term of this sequence is 3n + 2.

If you mean: 15 11 7 3 then the nth term is 19-4n

5, 8, 11, 14 and 17.

Un = 4n - 13.

It is: nth term = 5-4n and so the next term will be -19

The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11