What is the product of y and 10
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
The sum of x and y decreased by their product is (x + y)- xy.
The product of 5 and Y is simply the result of multiplying 5 by the value of Y. In mathematical terms, this can be represented as 5 * Y. The product will vary depending on the specific value assigned to Y.
You can set this up as follows... Let the two numbers be defined as x and y. Then, x * y = 96 x - y = 10 x = 96/y and substitute 96/y - y = 10 rearranging yields a quadratic equation 96 - y^2 = 10y or y^2 + 10y - 96 = 0 The solution(s) to the quadratic equation are given by: y = (-b +/- sqrt(b^2-4ac)) / 2a y = (-10 +/- sqrt(100 - 4(-96))) / 2 y = (-10 + 22 ) / 2 = 6 y = (-10 - 22 ) / 2 = -16 So, y can be 6 or -16 making x = 16 or -6 So you have two answers, (x,y) = (16,6) or (x,y) = (-6,-16)
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To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).
x = 10, y = 25
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
The product of the abscissa (x-coordinate) and the ordinate (y-coordinate) being ten means that for any point ((x, y)) on the Cartesian plane, the equation (x \cdot y = 10) holds true. This relationship describes a hyperbola in the xy-plane, where the coordinates can take on various pairs of values (e.g., ((1, 10)), ((2, 5)), ((5, 2)), ((10, 1)), etc.). Each pair represents a point where the product of the x and y values equals ten.
The two numbers that have a difference of 6 and a product of 40 are 10 and 4. To find them, you can set up the equations: ( x - y = 6 ) and ( xy = 40 ). Solving these gives you ( x = 10 ) and ( y = 4 ) (or vice versa).
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
The product of two consecutive numbers, where the smaller number is ( y ), can be expressed as ( y(y + 1) ). This is because the next consecutive number after ( y ) is ( y + 1 ). Therefore, the product is ( y^2 + y ).
The sum of x and y decreased by their product is (x + y)- xy.
The product of 5 and Y is simply the result of multiplying 5 by the value of Y. In mathematical terms, this can be represented as 5 * Y. The product will vary depending on the specific value assigned to Y.
Yes. You must solve the two simultaneous equations below: x * y = 18 x - y = 10 When you do so, you will get two solution sets: x = 11.557 (approx.) y = 1.557 (approx.) and x = -1.557 (approx.) y = -11.557 (approx.)