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Find the domain and range of sin x - cos x?
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
What is the domain and range of y equals x2 plus 1?
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
What is the domain and range of the function y equals 1 divided by x squared?
The domain of y = 1/x2 is all numbers from -infinity to + infinity except zero. The range is all positive numbers from zero to +infinity, except +infinity.
What is is the domain and range of y equals 2x-8?
10
What is the cosines inverse of 2?
The range of cosine is [-1, 1] which is, therefore, the domain of cos-1. As a result, cos-1(2) is not defined.
Find the domain and range of sinx?
the domain is all real numbers the range is from -1 to +1
What is the range of the function y equals x2 plus 1?
The answer depends on the domain. If the domain is the whole of the real numbers, the range in y ≥ 1. However, you can choose to have the domain as [1, 2] in which case the range will be [2, 5]. If you choose another domain you will get another range.
How do you find the range of the function with the given domain?
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
Find the domain and range of sin x - cos x?
sin(x)-cos(x) = (1)sin(x)+(-1)cos(x) so the range is sqrt((1)^2+(-1)^2)=1 and the domain is R <><><><><> The domain of sin x - cos x is [-infinity, +infinity]. The range of sin x - cos x is [-1.414, +1.414].
What is the range of y equals -sin x?
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
What is the range of the function f(x) 4x plus 9 given the domain D -4 -2 0 2?
The range is {-7, 1, 9, 17}.
What is the domain and range of y equals x2 plus 1?
if y = x2 + 1 Then the minimum value of y is 1, which happens at the point (0, 1). It lies in the domain of real numbers. i.e. {y | y ≥ 1, y ∈ ℝ}
Find the domain and range of the relation and state whether or not the relation is a function 1 4 1 5 1 6 1 7?
Any answers?
What is the domain of g x equals the square root of x plus 1?
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
What is the domain and range of y equals the square root of four minus x squared?
The domain and the range depends on the context. For example, the domain and the range can be the whole of the complex field. Or I could define the domain as {-2, 1, 5} and then the range would be {0, 3, -21}. When either one of the range and domain is defined, the other is implied.
Why 1 plus 1 is 2 two?
It is because that is how "plus" is normally defined. But 1 plus 1 need not be two. It all depends on the domain and range that you are working with and what you mean by the binary operation "plus". If 1 means make an about turn, and "plus" means "follow it with", then 1 plus 1 is "make an about turn" and then "make an about turn". If you do that you are back where you started. So in this case, 1 plus 1 is the same as zero.
What is the range of with domain 1 and 2 and 3 and 4?
The range could be anything. Without parameters specified, the domain of {1,2,3,4} could have any range. This problem is unsolvable.
