If the sum of its parallel sides is 6.5 cm
Then its height is 52/6.5 = 8 cm
Check: 0.5*6.5*8 = 26 square cm
It is double the length of the base, in square units.
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
Using Pythagoras: 62+32 = 45 and the square root of this is the altitude
They are tiles whose length is the same as their breadth.
100 cm
It is double the length of the base, in square units.
Using Pythagoras' theorem it works out as 10.5 units of measurement
well since we know that the area of a isosceles tapezoid is the height(altitude)times twice the median divided by two, so the answer is 9(2)(12)/2=108
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
Using Pythagoras: 62+32 = 45 and the square root of this is the altitude
Area = 0.5*12*8 = 48 square units
If the length of a side of an equilateral triangle = 8√3, then the altitude bisects the base forming a right angled triangle. The side measuring 8√3 is the hypotenuse, the altitude (A) is one leg and half the base length is the second leg. By Pythagoras, (8√3)2 = (4√3)2 + A2 : A2 = (64 x 3) - (16 x 3) = 48 x 3 = 144 Therefore the altitude, A = √144 = 12
45
A Square
They are tiles whose length is the same as their breadth.
100 cm
7 inches