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Q: What is the area of a triangle whose base is 12 and whose altitude is 8?

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It is double the length of the base, in square units.

The area of triangle is : 60.0

The area of triangle is : 64.0

Area = 0.5*base*altitude

A base is normally a line and therefore has no area; the area of a triangle is half of base x altitude.

altitude(height)=(Area * 2) /length(Base)

Area = 0.5*base*altitude

Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet

The area of triangle is : 80.0

Let the given area is 10cm. Base of the triangle is 4 cm. altitude of triangle=? Area= 1/2 x Base x altitude 10= 1/2 x 4x altitude 10=2 x altitude 10/2= altitude 5= altitude Hence, altitude of the triangle is 5 cm.

70

Area of a triangle = (0.5) * (Base) * (Altitude) = (0.5) * (6 meters) * (8 meters) = 24 square meters

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