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Find the function whose inverse is the same as the function itself?
Wiki User
∙ 14y ago
f ( x ) = (x-2)/(x-1)
if y = (x-2)/(x-1)
yx-y= x - 2
yx-x= -2+y
x(y-1)=y-2
x = (y-2)/(y-1)
so g ( x ) the inverse function is also (x-2)/(x-1)
Wiki User
∙ 14y ago
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