2
111
The sum of the digits in each multiple is 9 . It also works just fine for ' 1 '.
To find a common multiple for 2, 4, and 7 with a digit sum of 11, we first need to find the multiples of each number. The multiples of 2 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, and so on. The multiples of 4 are 4, 8, 12, 16, 20, and so on. The multiples of 7 are 7, 14, 21, 28, 35, and so on. By examining the lists, we find that the number 28 is a common multiple for 2, 4, and 7 with a digit sum of 11.
8, 12, 16 & 208 + 12 = 20
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
45, 60, and 75
91
To find the sum of multiple numbers means to add them all together. In this case, the sum of 49, 529, and 308 is equal to 886.
(1+2+3)*4 = 6*4 = 24
1601
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
56, 63, 70 and 77