2
111
The sum of the digits in each multiple is 9 . It also works just fine for ' 1 '.
8, 12, 16 & 208 + 12 = 20
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
91
45, 60, and 75
To find the sum of multiple numbers means to add them all together. In this case, the sum of 49, 529, and 308 is equal to 886.
(1+2+3)*4 = 6*4 = 24
1601
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
The numbers must total 888/8 ie 111. The middle number is 1/3 of 111 ie 37 so the three numbers are 36, 37 and 38 and multiples are 288, 296 and 304.
56, 63, 70 and 77