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How do you factor 12y squared plus 11y plus 2?
(4y + 1)(3y + 2)
Factor 3x squared plus 6xy plus 3y squared?
(3x + 3y)(x + y) = 3(x + y)2
Factor 3x squared - 3y squared?
0
Factor 3y cubed - 12y squared plus 4y?
y(3y^2 - 12y + 4)
What is the value of y when x equals 1 and y equals 3 plus 2x?
x=1y=2x+3y=2*1 + 3y=5
What is the gcf of 3y squared and 24y squared?
The GCF is 3y^2.
What is 3y squared?
9y^2
How do you factor 12y squared plus 11y plus 2?
(4y + 1)(3y + 2)
5y squared - 2 y squared equals 6 is a?
i think its 3y squared
Factor 3x squared plus 6xy plus 3y squared?
(3x + 3y)(x + y) = 3(x + y)2
What is -2(3y) squared?
what number is y?
Factor 3x squared - 3y squared?
0
Factor 3y cubed - 12y squared plus 4y?
y(3y^2 - 12y + 4)
What is the value of y when x equals 1 and y equals 3 plus 2x?
x=1y=2x+3y=2*1 + 3y=5
2x plus 3y equals -1 5x-2y equals -12?
2x+3y=-1 and 5x-2y=-12 3y=-2x-1 and -2y=-5x-12 y=(-2/3)x-1/3 and y=(5/2)x+6 Substitute the first value of y into the second equation (-2/3)x-1/3=(5/2)x+6 (-19/6)x=19/3 x=-2 Plug this value of x into the first equation 2(-2)+3y=-1 -4+3y=-1 3y=3 y=1 Check your results by plugging x=-2 and y=1 into the second equation 5(-2)-2(1)=-12 -10-2=-12 -12=-12 This is correct, so the final answer is x=-2 and y=1
2x plus 3y equals 3 and 4x minus 3y equals 9. What value of y is part of the solution for this system of equations?
There are two simultaneous equations, so to solve for y, eliminate x: 1) 2x + 3y = 3 2) 4x - 3y = 9 Multiply equation (1) by 2 giving: 1) 4x + 6y = 6 2) 4x - 3y = 9 Next, subtract equation (2) from equation (1), giving: (4x - 4x) + (6y - -3y) = 6 - 9 → 9y = -3 → y = -1/3
What is the simplified form of the quantity 15 x y squared over x squared plus 5x plus 6 all over the quantity 5 x squared y over 2x squared plus 7x plus 3?
((15xy2)/(x2+5x+6))/((5x2y)/(2x2+7x+3)) =(15xy2/5x2y)*(2x2+7x+3)/(x2+5x+6) =(3y/x)*(((2x+1)(x+3))/((x+2)(x+3) =(3y(2x+1))/(x(x+2)) =(6xy+3y)/(x2+2x)
