(3x + 3y)(x + y) = 3(x + y)2
3x(6x - 1)
y(3y^2 - 12y + 4)
(3y - 5)(y + 5)
3x(2x + 1)
(3x + 3y)(x + y) = 3(x + y)2
There is not an answer but you can factor it.3x+3y=3(x+y)
This is like a² - b², with a = 9x² and b = 9y². This can be factored as (a - b)(a + b), then substitute for a & b: (9x² - 9y²)(9x² + 9y²), then (9x² - 9y²) can factor to (3x - 3y)(3x + 3y) so we have: (3x - 3y)(3x + 3y)(9x² + 9y²)
It is: 3y(2y-3x) when factored
-3(x + y + z)
3xy + 3y2 = 3y (x + y)
It is: 3x*(x+7)
x(3x - 2)
(3x-4)(3x+4)
3x(6x - 1)
y(3y^2 - 12y + 4)
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