4!x4+4!÷4!!
By using the PEMDAS/BODMAS rules, you see the operators +,x and ÷.
First do the division, then multiplication, then only you do the addition will make 99.
Factorial = 4!=24.
Double factorial = 4!!=8
Steps:
4!x4+4!÷4!!
=24x4+24÷8
=24x4+3
=96+3
=99
Therefore, 4!x4+4!÷4!!=99.
To make 11 using four fours, you can use the following equation: ( 4 \times 4 - 4 - 4 = 11 ). Here, you multiply two fours to get 16, then subtract two fours to reach 11. This creatively utilizes the four fours while adhering to the mathematical operations allowed.
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
fourteen take away four and then add a four and times by (2 times 4)
4! - 44/4 = 24 - 11 = 13
You can make the number 10 using four fours with the following mathematical expression: ( (4 \times 4) - (4 + 4) ). This simplifies to ( 16 - 8 = 8 ), which is incorrect. Instead, try this: ( (4 \times 4) / 4 + 4 = 10 ). This correctly uses four fours to achieve the desired result.
You can make 32 using four fours by employing mathematical operations as follows: [ 32 = (4 \times 4) \times (4 - 4) + 4! ] However, a simpler expression is: [ 32 = (4 + 4) \times (4 + 4) ] Here, you add two fours to get 8 and then multiply it by another pair of fours to achieve 32.
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
There are several ways of making 10 using four fours. Amongst them are the following: (44 - 4)/4 = 10 44 / 4.4 = 10 4 + sqrt(4) + sqrt(4) + sqrt(4) = 10
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
(4+4)/4 + 4
4 × ((4 ÷ 4) + 4)=20