4!x4+4!÷4!!
By using the PEMDAS/BODMAS rules, you see the operators +,x and ÷.
First do the division, then multiplication, then only you do the addition will make 99.
Factorial = 4!=24.
Double factorial = 4!!=8
Steps:
4!x4+4!÷4!!
=24x4+24÷8
=24x4+3
=96+3
=99
Therefore, 4!x4+4!÷4!!=99.
Using four fours, you can get 19 with the following sum: 4! - 4 - (4 / 4) That is, four factorial minus four - (four divided by four) - 24 - 4 - (4 / 4) = 19
fourteen take away four and then add a four and times by (2 times 4)
4! - 44/4 = 24 - 11 = 13
A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!
Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.
As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!
There are several ways of making 10 using four fours. Amongst them are the following: (44 - 4)/4 = 10 44 / 4.4 = 10 4 + sqrt(4) + sqrt(4) + sqrt(4) = 10
(4+4)/4 + 4
4 × ((4 ÷ 4) + 4)=20
One way to use four fours to make 25 is 4 + 4 + 4 + √4, which equals 25.
4+4-(4/4)=7
11 = 4/.4 + 4/4