8(y-9)
The only thing you can do to this is factor it... (4x + 8y)(4x - 8y)
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
Not sure which you mean, take your pick: (8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or 8y3+27=(2y+3)(4y2-6y+9)
8(y - 1)
8y + 7y = 15ySo [ 8y + 9 + 7y ] = 15y + 9If you want to get fancy and factor that expression, it's 3(5y + 3) .
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
2(8y + 1)
72 is not a factor of 18; 18 is a factor of 72.
The highest factor of 72 is 72.
The highest common factor of 36 and 72 is 36
The GCF of 72 and 144 is 72. Since 72 is a factor of 144, it is automatically the GCF.
No, 72 is a factor of 144.