1 to 1000. Pilandromic 108
There are 90 palindromic numbers between 100 and 1000
1001 - 1991, etc = 10, x (2,3,4,5,6,7,8,9) 8 = 80
1001,1111,1221,1331,1441,1551,1661,1771,1881,1991,2002,2112,2222,2332,2442,2552,2662,2772,2882,2992,3003,3113,3223,3333,3443,3553,3663,3773,3883,3993,4004,4114,4224,4334,4444,4554,4664,4774,4884,4994: 40 numbers in all.
If you think about the digits, you can rewrite them as ABBA, with A being one digit and B being another: A can be 1-9 and B can be 0-9. Since A has to be 1, B can be 0-9, leaving 10 palindromic numbers.
a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)
There are 107 numerical palindromes between the numbers 1 and 1000, starting from 2 to 999.
Magsolve ka Naman boy!
There are 900 three-digit whole numbers between 1 and 1000
90 Source: Answer in back of Algebra I Book :)
By including the number 1000, the digit 1.
11000
Zero