Assuming that the question is in the context of complex number, the product of any real number with itself (its square) is a real number.
For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i
Assuming that the question is in the context of complex number, the product of any real number with itself (its square) is a real number.
Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.
Graphically, the conjugate of a complex number is its reflection on the real axis.
The conjugate of a complex number is formed by changing the sign of its imaginary part. Since (6 + \sqrt{2}) is a real number (with no imaginary part), its conjugate is simply itself: (6 + \sqrt{2}).
Their sum is real.
When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.
For example, the conjugate of 5 + 3i is 5 - 3i. The graph of the first number is three units above the real number line; the second one is three units below the real number line.
Aamir jamal; All real numbers are complex numbers with 0 as its imaginary part.A real number is self-conjugate. e.g;a+0i self conjugate =a-0i i=iota
A number multiplied by its complex conjugate will result in a real number. Also, adding a number to its conjugate will result in a real number. But typically the multiplication is what is used.
its the same as itself. since there is no radical part
A conjugate number refers to a complex number having both the imaginary and real parts of opposite signs and equal magnitude.