Assuming that the question is in the context of complex number, the product of any real number with itself (its square) is a real number.
For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i
Assuming that the question is in the context of complex number, the product of any real number with itself (its square) is a real number.
Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.
Graphically, the conjugate of a complex number is its reflection on the real axis.
Their sum is real.
When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.
For example, the conjugate of 5 + 3i is 5 - 3i. The graph of the first number is three units above the real number line; the second one is three units below the real number line.
Aamir jamal; All real numbers are complex numbers with 0 as its imaginary part.A real number is self-conjugate. e.g;a+0i self conjugate =a-0i i=iota
A number multiplied by its complex conjugate will result in a real number. Also, adding a number to its conjugate will result in a real number. But typically the multiplication is what is used.
its the same as itself. since there is no radical part
A conjugate number refers to a complex number having both the imaginary and real parts of opposite signs and equal magnitude.
The conjugate will have equal magnitude. The angle from the real axis will be the same angle measure (but opposite direction).