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Q: How can 4 boys and 5girls sit in a row such that no two girls sit together?

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6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.

It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.

Do 6 X 6 it equals 36..that's how many

Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.

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The largest number of kids that can be in each row while maintaining the same number of boys and girls in each row would be 6. This would result in 4 rows with 6 girls and 3 boys each.

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6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.

It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.

Do 6 X 6 it equals 36..that's how many

There are seven different layouts, if none of the people have identities. If each girl and boy must be identified, then there are 336 different layouts. Each of these can be doubled if the end that you start counting from is also defined.

Yes, you can be a female in Saints Row 3.

Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.

This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381

1out of 3

you have a 75% chance

A row of houses all joined together is called: terraced house.