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To ensure that no two girls sit together, we first arrange the 4 boys in a row, which can be done in (4!) ways. This creates 5 possible gaps (before the first boy, between boys, and after the last boy) for the girls to occupy. We can select 5 out of these 5 gaps, and the 5 girls can be arranged in these gaps in (5!) ways. Therefore, the total arrangements are (4! \times 5!).
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There are five girls and five boys at a party In how many ways can they be seated in a row of six?
25
In how many ways can 3 girls and 5 boys be arranged in a row so that all the 3 girls are together?
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
What is the probability of having 7 girls in a row?
It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.
How many ways can 3 boys and 2 girls stand in a row so that the two girls are not next to each other?
To find the number of ways 3 boys and 2 girls can stand in a row such that the girls are not next to each other, first calculate the total arrangements without restrictions, which is (5!) (for 5 individuals), yielding 120 arrangements. Next, calculate the arrangements where the two girls are together by treating them as a single unit, resulting in (4!) arrangements for the group and (2!) arrangements for the girls within that group, giving (4! \times 2! = 48). Finally, subtract the restricted arrangements from the total: (120 - 48 = 72). Thus, there are 72 ways for the boys and girls to stand so that the girls are not next to each other.
How many ways can 6 boys and 6 girls stand in a row?
Do 6 X 6 it equals 36..that's how many
If there are 24 girls and 18 boys in rows what would be thelargest number that the number of kids in each row?
The largest number of kids that can be in each row while maintaining the same number of boys and girls in each row would be 6. This would result in 4 rows with 6 girls and 3 boys each.
There are five girls and five boys at a party In how many ways can they be seated in a row of six?
25
In how many ways can 3 girls and 5 boys be arranged in a row so that all the 3 girls are together?
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
What is the probability of having 7 girls in a row?
It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.
How many ways can 3 boys and 2 girls stand in a row so that the two girls are not next to each other?
To find the number of ways 3 boys and 2 girls can stand in a row such that the girls are not next to each other, first calculate the total arrangements without restrictions, which is (5!) (for 5 individuals), yielding 120 arrangements. Next, calculate the arrangements where the two girls are together by treating them as a single unit, resulting in (4!) arrangements for the group and (2!) arrangements for the girls within that group, giving (4! \times 2! = 48). Finally, subtract the restricted arrangements from the total: (120 - 48 = 72). Thus, there are 72 ways for the boys and girls to stand so that the girls are not next to each other.
How many ways can 6 boys and 6 girls stand in a row?
Do 6 X 6 it equals 36..that's how many
Two girls and four boys are to seated in a row in such a way that the girls do not sit together in how many different ways can it be done?
There are seven different layouts, if none of the people have identities. If each girl and boy must be identified, then there are 336 different layouts. Each of these can be doubled if the end that you start counting from is also defined.
Can you do girls in saints row 3?
Yes, you can be a female in Saints Row 3.
What is the probability of a woman giving birth to 6 daughters in a row?
Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.
What is the probability of having three boys in a row?
This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381
What is the chance of a couple having 3 boys in a row?
1out of 3
What is the probability of having three girls in a row?
you have a 75% chance
