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They are simply referred to as local minimums and maximums. Experience: Algebra 2 Advanced
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
A quadratic can be drawn as a graph and it is either "U" shaped or "n" shaped. If it were "U" shaped, the minimum value qould be the lowest point of the "U". If "n" shaped, maximum would be the top.
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A global minimum is a point where the function has its lowest value - nowhere else does the function have a lower value. A local minimum is a point where the function has its lowest value for a certain surrounding - no nearby points have a lower value.
It can't - unless you analyze the function restricted to a certain interval.
vertex
Apex.
By taking the derivative of the function. At the maximum or minimum of a function, the derivative is zero, or doesn't exist. And end-point of the domain where the function is defined may also be a maximum or minimum.
They are simply referred to as local minimums and maximums. Experience: Algebra 2 Advanced
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
A quadratic can be drawn as a graph and it is either "U" shaped or "n" shaped. If it were "U" shaped, the minimum value qould be the lowest point of the "U". If "n" shaped, maximum would be the top.
The vertex, or maximum, or minimum.
A maximum or minimum is generally referred to as an extrema.
Some do and some don't. It's possible but not necessary.
The answer depends on the form in which the quadratic function is given. If it is y = ax2 + bx + c then the x-coordinate of the turning point is -b/(2a)
The critical point is called the point at which a function's derivative is zero or undefined. At this point, the function may have a local maximum, minimum, or an inflection point.