3*3 - 3/3
3³ ÷ 3 x 3 = 27
3*3 + 3/3 = 10
The following equation must be solved using BEDMAS to get the final answer as 7 using the no. 3 four times: 3/3 + 3 + 3= 1 + 3 + 3= 7
The number is 3
3 + 3 + 3/3
-4/3 or -1.3333
3
( (3x3) +3 ) /3=4
3
4X-3
5*4+3+2
4(N-3) is the formula, do the math from there and you get "N-3"