make by dissolving 2g or glucose (or dextrose) in 100 ml water or by grinding one glucose tablets (4 grams/tablet; found in drugstores) in 200ml of water.
335.7*1.06 = 355.842 grammes
2.3 percent glucose solution and .3 percent sodium solution
1:10 ratio.
You stare at it
200 grams/1,000 mL x 100= 20%
Yes, during process of osmoses the solvent from higher concentration to lower concentration moves through semipermeable membrane, the 2% solution has lower concentration of solute therefore higher concentration of solvent.
You need 36,03 g glucose.
sugar and water?
2% glucose solution is considered as a hypotonic solution for that the solution will enter the semi-permeable membrane of the red blood cells causing the cells to explode or burst. Why? It's because RBCs have a higher concentration inside it than that of the 2% glucose solution so the solution will enter the cells.
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
The solution's mass is 0.0043 kg
Not if the solution contained only glucose and water.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
Its a mixture!
Dissolve 10 g pure glucose in 100 mL distilled water.
the solution in the balloon is hypertonic relative to the solution in the breaker. is this true
Glucose is the solute; water is the solvent.