make by dissolving 2g or glucose (or dextrose) in 100 ml water or by grinding one glucose tablets (4 grams/tablet; found in drugstores) in 200ml of water.
A 25 percent glucose solution means that there are 25 grams of glucose in every 100 milliliters of the solution. Therefore, in 25 milliliters of a 25 percent glucose solution, there would be 6.25 grams of glucose. This concentration is commonly used in medical and laboratory settings for various applications.
335.7*1.06 = 355.842 grammes
2.3 percent glucose solution and .3 percent sodium solution
1:10 ratio.
A 5 percent dextrose solution contains 5 grams of dextrose (glucose) per 100 milliliters of solution. Therefore, in one liter (1000 milliliters) of a 5 percent dextrose solution, there would be 50 grams of glucose.
Yes, during process of osmoses the solvent from higher concentration to lower concentration moves through semipermeable membrane, the 2% solution has lower concentration of solute therefore higher concentration of solvent.
Dissolve 10 g pure glucose in 100 mL distilled water.
sugar and water?
To prepare a 50mm glucose solution, you would need to dissolve 9g of glucose in enough water to make 100mL of solution. This would give you a solution with a concentration of 50mm (millimolar).
2% glucose solution is considered as a hypotonic solution for that the solution will enter the semi-permeable membrane of the red blood cells causing the cells to explode or burst. Why? It's because RBCs have a higher concentration inside it than that of the 2% glucose solution so the solution will enter the cells.
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
Dissolve 90 g of glucose in a small volume of water, and then add more water until the total volume of the solution is 1 L.
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
To make a 2 M solution of glucose in 100mL, you would need to calculate the molecular weight of glucose (180.16 g/mol) and then use the formula: mass (g) = molarity (M) x volume (L) x molecular weight (g/mol) mass = 2 mol/L x 0.1 L x 180.16 g/mol = 36.032 grams of glucose.
To prepare a 10% glucose solution, you would mix 10 grams of glucose with enough water to make a total solution volume of 100 ml. This means the final solution would contain 10 grams of glucose and 90 ml of water.
Glucose solution is a homogeneous mixture because it is composed of glucose dissolved in water, making it uniform throughout.