(3*4 + 6 - 1)*2*5
= (12 + 6 - 1)*10
17*10 = 170
To find the least number divisible by 23456 with a remainder of 1, you need to find the least common multiple (LCM) of 23456 and the number 1 more than it. The LCM of two numbers is the smallest number that is a multiple of both numbers. In this case, you would calculate the LCM of 23456 and 23457. The LCM can be found by multiplying the two numbers and then dividing by their greatest common divisor.
170: 1, 2, 5, 10, 17, 34, 85, 170
The numbers that make up 170 is (0 + 0 + 1 + 2 + 67 + 60 + 27 + 12 + 1).
7
To solve this problem, we need to understand the relationship between the variables. If "apd" equals 109 and "1" equals 17, we can deduce that the value of "a" is 10 and the value of "b" is 1. Therefore, if we substitute these values into the equation "bpd," we get 1 * 10 * 17, which equals 170. So, "bpd" equals 170.
1, 2, 5, 10, 34, 85 and 170
1, 2, 5, 10, 17, 34, 85, 170.
180 * * * * * Wrong! There are 6: 12345, 12346, 12356, 12456, 13456 and 23456. And that is it! No more.
1 170 000 000
The only answers are 1 and 2. Meaning 1 and 2 are the only numbers that you can divide 170 and 12 by and get whole numbers (no decimals) as answers. 170 / 1 = 170 12 / 1 = 12 170 / 2 = 85 12 / 2 = 6 Try it with any other number and you'll see that at least one of your answers will not be a whole number.
The most obvious answer would be 5, since 23,455 is divisible by 5 (as are all whole numbers that end in 5 or 0).
170 grams is equal to about 6 ounces (weight only)