All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
-4
x =6 y = 8 10x = 60 8y = 64 10x + 8y = 124
(7x + 8)(7x - 9)
8(y - 1)(y^2 + y + 1)
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
8(y - 1)
8(y-9)
9 minus 8
000000
( 2xy - 4x ) + ( 8y - 16)2 ( xy - 2x ) + 2 ( 4y - 8 ) Answer
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
-16
(x + 1)(x - 8)
0
x 3-8