No. The range of the projectile thrown at 90 degrees is 0. It goes straight up and then straight down!
The half maximum range of a projectile is launched at an angle of 15 degree
The correct angle of throwing a javelin is 45 degree.The physics concept behind this is known as impulse.According to this law if an object is thrown at an angle of 45 degree it travels much range(horizontal distance) than throwing at any other angle this law not only applies for javelin but also for firing an cannon or shooting a gun on an arrow into the space.
1. You need to know the velocity of the projectile (V0) 2. The expressions for the range and height assume no air resistance (in vacuum) 3. The units must be consistent e.g. metres and g = 9.81 m/s2 Range in metres for 30 degree launch angle = sin 60 x V02 / 9.81 Range in metres for 45 degree launch angle = sin 90 x V02 / 9.81 Range in metres for 60 degree launch angle = sin 120 x V02 / 9.81 Max. height in metres for 30 degree launch angle = (V0 x sin 30)2 / 2g Max. height in metres for 45 degree launch angle = (V0 x sin 45)2 / 2g Max. height in metres for 60 degree launch angle = (V0 x sin 60)2 / 2g 2g is of course 9.81 x 2 = 19.62 m/s2 For interest, at 45 degree launch angle the max. height is 25% of the range.
Both the arrows will cover equal horizontal distance as their angles are at an difference from 45 degree. Horizontal range is maximum at 45 degrees and decreases equally on sum or difference of an angle from 45. But vertical distance increases on addition of an angle from 45 and decreases on subtraction of angle from it. For more details, contact at saqibahmad81@yahoo.com
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
It depends on the weapon. A rifle will have a very low angle--maybe ten degrees. A mortar needs a very high angle to give a good range. And a howitzer needs about a 45 degree angle to give long range.
w2hen the angle of projection is larger than 45 degree the height attained will be more but the range is again less.in this case angle is 30 degree which is less than 45 degree and 60 degree angle is greater than angle of 45 degree which have less range and is equal to range of 30 degree .so ranges are equal.
The half maximum range of a projectile is launched at an angle of 15 degree
No, but 110 degrees is an obtuse angle. An obtuse angle can be anything in the range (90, 180) degrees.
No. An obtuse angle has a measure in the range (90, 180) degrees. The angle in question is greater than the maximum value for an obtuse angle.
The correct angle of throwing a javelin is 45 degree.The physics concept behind this is known as impulse.According to this law if an object is thrown at an angle of 45 degree it travels much range(horizontal distance) than throwing at any other angle this law not only applies for javelin but also for firing an cannon or shooting a gun on an arrow into the space.
1. You need to know the velocity of the projectile (V0) 2. The expressions for the range and height assume no air resistance (in vacuum) 3. The units must be consistent e.g. metres and g = 9.81 m/s2 Range in metres for 30 degree launch angle = sin 60 x V02 / 9.81 Range in metres for 45 degree launch angle = sin 90 x V02 / 9.81 Range in metres for 60 degree launch angle = sin 120 x V02 / 9.81 Max. height in metres for 30 degree launch angle = (V0 x sin 30)2 / 2g Max. height in metres for 45 degree launch angle = (V0 x sin 45)2 / 2g Max. height in metres for 60 degree launch angle = (V0 x sin 60)2 / 2g 2g is of course 9.81 x 2 = 19.62 m/s2 For interest, at 45 degree launch angle the max. height is 25% of the range.
The [horizontal] range of a projectile is maximised when it shoots at a 45 degree angle. This is true if air resistance is ignored so that the only force acting on the projectile is gravity.
Both the arrows will cover equal horizontal distance as their angles are at an difference from 45 degree. Horizontal range is maximum at 45 degrees and decreases equally on sum or difference of an angle from 45. But vertical distance increases on addition of an angle from 45 and decreases on subtraction of angle from it. For more details, contact at saqibahmad81@yahoo.com
30
the longest range for any prjectile motion is theoritically 45 degree from horizon
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?