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You want to factor (x4 -91)
First notice that the factors of 91 are 1, 7, 13, and 91.
If we try them all , we see that x4 -91 is a prime polynomial.
Even though the polynomial is prime, that is cannot be factored over the set of rational numbers, it is factorable over the set of Irrational Numbers.
x4 - 91
= (x2)2 - (√91)2
= (x2 - √91)(x2 + √91)
= [x2 - (√√91)2](x2 + √91)
= (x - √√91)(x + √√91)(x2 + √91)
What else can I help you with?
How do you completely factor x to the fourth power minus y to the fourth power?
It is: (x-y)4
How do you factor completely x to the fourth power minus x squared minus 2?
(x2 + 1)(x2 - 2)
How do you factor 2x to the fourth power minus 162?
2x to the fourth power minus 162 equals -146
How do you factor completely x to the fourth power minus sixteen times x to the second power?
x^2(x - 4)(x + 4)
How do you factor completely x to the third power minus 216?
x cubed minus 216
Is y minus 3 a factor of y to the fourth power plus 2 y to the second power minus 4?
No.
How do you factor 9x to the fourth power minus 16y to the fourth power?
(3x^2 - 4y^2)(3x^2 + 4y^2)
How do you factor x squared minus x to the fourth?
x^2(1 - x)(1 + x)
How do you factor completely x to the fourth power minus 1?
So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).
How do you completely factor x to the fourth power minus eighty one?
Factor x4 - 81. Step 1: both numbers have square roots and have a minus sign between them so the first factor result is (x2+9)(x2-9). Step 2: (x2+9) does not factor, but (x2-9) factors to (x+3)(x-3). Step 3: Solution is (x2+9)(x+3)(x-3).
How do you factor 3x to the fourth minus 48?
3(x - 2)(x + 2)(x^2 + 4)
How do you factor completely x to the fourth power minus 16?
(x4 - 16) = (x2 + 4) (x2 - 4) = (x2 + 4) (x + 2) (x - 2)
