Three twelves is 36. Four twelves is 48. 36 - 48 = -12. Three twelfths - fourth twelfths equals minus one twelfth.
If: 3x = 48 Then: x = 16
If you mean 2x2 + 3x = (3x - 1)2 - x2 Then you can solve it this way: Expand: 2x2 + 3x = 9x2 - 6x + 1 - x2 Group like terms: 2x2 + 3x = 8x2 - 6x + 1 6x2 - 9x - 1 = 0 Complete the square: 6x2 - 9x = 1 x2 - 3x/2 = 1/6 x2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4)2 = 8/48 + 27/48 (x - 3/4)2 = 35/48 Solve for x: x - 3/4 = ± √(35/48) x - 3/4 = ± √(35/3) / 4 x = 3/4 ± √(35/3) / 4 x = [3 ± √(35/3)] / 4 If you mean something else, then you'll need to be clearer with your question.
48 = 144
48 minus 32 is 16.
Three twelves is 36. Four twelves is 48. 36 - 48 = -12. Three twelfths - fourth twelfths equals minus one twelfth.
If: 3x = 48 Then: x = 16
3x+12=x+48: 3x-x=-12+48 2x=36 x=18
If you mean 2x2 + 3x = (3x - 1)2 - x2 Then you can solve it this way: Expand: 2x2 + 3x = 9x2 - 6x + 1 - x2 Group like terms: 2x2 + 3x = 8x2 - 6x + 1 6x2 - 9x - 1 = 0 Complete the square: 6x2 - 9x = 1 x2 - 3x/2 = 1/6 x2 - 3x/2 + 9/16 = 1/6 + 9/16 (x - 3/4)2 = 8/48 + 27/48 (x - 3/4)2 = 35/48 Solve for x: x - 3/4 = ± √(35/48) x - 3/4 = ± √(35/3) / 4 x = 3/4 ± √(35/3) / 4 x = [3 ± √(35/3)] / 4 If you mean something else, then you'll need to be clearer with your question.
3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
75r^2-48 You can take out 3.So... 3(25r^2-16) 3-parenthesis-25r squared-minus-16-parenthesis (:
48 = 144
3x + 10x - 48 = 0 13x = 48 x = 3.692307692
48 minus 1.4 is 46.6
48 minus 32 is 16.
3x - 5 = 48 So 3x = 53 and x = 53/3 = 17.66...
(n - 4)(n - 12)