It's possible
No matter what the angles are:* Express the vectors in Cartesian (rectangular) coordinates; in two dimensions, this would usually mean separating them into an x-component and a y-component. * Add the components of all the vectors. For example, the x-component of the resultant vector will be the sum of the x-components of all the other vectors. * If you so wish (or the teacher so wishes!), convert the resulting vector back into polar coordinates (i.e., distance and direction).
They are the projections, onto the x and y [Cartesian] axes, of a point whose polar coordinates are (R, theta). It's a common Trig way to express a point when a radius is rotated around a given angle. For example, where exactly would the edge of a two foot gate lie if the gate opened 30 degrees? R is two feet. Two times cosine 30 is the x coordinate and two times sine 30 is the y coordinate.
Often people involved in industrial production will use polar graphs to program their machines; take, for, example, a pretzel-making machine. They can graph the path the "dough-shaping" machine must follow on a polar graph.
Some of them but not all. For example, uniqueness. The rectangular coordinates (x, y) represent a different point if either x or y is changed. This is also true for polar coordinate (r, a) but only if r > 0. For r = 0 the coordinates represent the same point, whatever a is. Thus (x, y) has a 1-to-1 mapping onto the plane but the polar coordinates don't.
There are several topics under the broad category of trigonometry. * Angle measurements * Properties of angles and circles * Basic trigonometric functions and their reciprocals and co-functions * Graphs of trigonometric functions * Trigonometric identities * Angle addition and subtraction formulas for trigonometric functions * Double and half angle formulas for trigonometric functions * Law of sines and law of cosines * Polar and polar imaginary coordinates.
the equation that convert from cartesian to polar coordinates and vice versa r = sqrt (x*x+y*y); phi = atan2 (y, x); x = r*cos (phi); y = r*sin (phi);
x2+y2=2y into polar coordinates When converting Cartesian coordinates to polar coordinates, three standard converstion factors must be memorized: r2=x2+y2 r*cos(theta)=x r*sin(theta)=y From these conversions, you can easily get the above Cartesian equation into polar coordinates: r2=2rsin(theta), which reduces down (by dividing out 1 r on both sides) to: r=2sin(theta)
Set x = r*sin(t) and y = r*cos(t) then r = sqrt(x^2 + y^2) and t = arctan(y/x) if x not 0, t = pi/2 if x = 0.
The y-intercept (or y-intercepts) of an equation is where x = 0. Replace x with zero in the equation, and solve for y.The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
Some problems are easier to solve using polar coordinates, others using Cartesian coordinates.
The equation in Cartesian coordinates is x2 + y2 = 6 But much simpler are the polar coordinates: r = 6 and 0 ≤ q < 360 degrees.
The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
Polar Co-ordinates are non-Cartesian co-ordinates. Since most of the Graphics Package do not support non-Cartesian co-ordinates,Polar co-ordinates should be converted to Cartesian form.
If the polar coordinates of a complex number are (r,a) where r is the distance from the origin and a the angle made with the x axis, then the cartesian coordinates of the point are: x = r*cos(a) and y = r*sin(a)
polar
You do not have to. You could use polar coordinates, if you prefer.
no