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The rectangle is 14 units x 0.5 units:

Let a and b be the dimensions of the rectangle

Perimeter = 2a + 2b = 29

2a + 2b = 29

=> a + b = 14.5

=> b = 14.5 - a

Area = a * b = 7

=> a * (14.5 - a) = 7

=> 14.5a - a2 = 7

=> a2 - 14.5a + 7 = 0

Solving the quadratic equation gives a=14 or a=0.5

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Q: How do you draw a rectangle with an area of 7 with a perimeter of 29?
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