The rectangle is 14 units x 0.5 units:
Let a and b be the dimensions of the rectangle
Perimeter = 2a + 2b = 29
2a + 2b = 29
=> a + b = 14.5
=> b = 14.5 - a
Area = a * b = 7
=> a * (14.5 - a) = 7
=> 14.5a - a2 = 7
=> a2 - 14.5a + 7 = 0
Solving the quadratic equation gives a=14 or a=0.5
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
2 * 12 + 2 * 2.5 = 29
Let the dimensions be x and y:- If: 2x+2y = 29 then y =14.5-x If: xy = 50.3125 then x(14.5-x) = 50.3125 Expanding brackets and transposing terms: 14.5x -x^2 -50.3125 = 0 Using the quadratic equation formula: x = 8.75 or x = 5.75 Therefore dimensions of the rectangle are: length = 8.75 cm and width = 5.75 cm Check: 2(8.75+5.75) = 29 cm Check: 8.75*5.75 = 50.3125 square cm
If it's a rectangle/parallelogram then 1 metre. If it's not then more info is needed
29
It decreases. viz: perimeter of 5 x 5 square is 20 units, perimeter of 12.5 x 2 rectangle is 29 units...
Another Answer:The length of the rectangle is 29 cm because 2*(29+23) = 104 cm which is the perimeter
The perimeter is 11 + 5 + 13 = 29 inches.
Perimeter = (1 + 29 + 1 + 29) = 60 ft Area = (1 x 29) = 29 square feet
Anything more than 21. (29 + 21 + 29 + 21) = 100
2 * 12 + 2 * 2.5 = 29
Let the dimensions be x and y:- If: 2x+2y = 29 then y =14.5-x If: xy = 50.3125 then x(14.5-x) = 50.3125 Expanding brackets and transposing terms: 14.5x -x^2 -50.3125 = 0 Using the quadratic equation formula: x = 8.75 or x = 5.75 Therefore dimensions of the rectangle are: length = 8.75 cm and width = 5.75 cm Check: 2(8.75+5.75) = 29 cm Check: 8.75*5.75 = 50.3125 square cm
29
If it's a rectangle/parallelogram then 1 metre. If it's not then more info is needed
You can't tell the area from the perimeter. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeter of 60 m: 1 x 29 . . . . . area = 29 2 x 28 . . . . . 56 3 x 27 . . . . . 81 4 x 26 . . . . 104 5 x 25 . . . . 125 6 x 24 . . . . 144 7 x 23 . . . . 161 8 x 22 . . . . 176 9 x 21 . . . . 189 10 x 20 . . . 200 12 x 18 . . . 216 14 x 16 . . . 224 15 x 15 . . . 225 0.1 x 29.5 . . area = 2.95
Area = length x width, so length = area/width = 116/4 = 29 yds
Suppose the length is L and the breadth is B. Then since perimeter = 58, 2*(L+B) = 58 so that L+B = 29 that is L = 29-B Now Area = L*B = 204 That is (29-B)*B = 204 Or B2 - 29B + 204 = 0 which is equivalent to (B-12)*(B-17) = 0 So, using L+B = 29, L and B are 12 and 17.