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Q: How do you factor 36 times d cubed plus 24?

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2(x + 3)(x^2 + 4)

(8x + 9)(3x^2 - 1)

2 cubed = 2*2*2 =8. 8+8+8= 24

2

17 + 8 x 3 = 17 + 24 = 41

(3x+12)(5x+2)

50 plus 24 times 12 is equal to 338.

2x+5x-24 7x2-24

4 is the greatest common factor: it goes into 20 5 times and 24 6 times.

See method below: Number of times each prime factor appears in the factorization of : Prime Factor Number 72 Number 120 Number 144 G.C.F 2 3 3 4 3 3 2 1 2 1 5 0 1 0 0 GCF = 2 cubed (2 times 2 times 2)= 8. 8 times 3 = 24 Therefore the HCF of 72 120 and 144 is 24

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions:24 plus or minus 6 times the square root of 14a = 46.44994432064365a = 1.5500556793563511

(5x - 3)(x + 8)

The question is somewhat ambiguous but it probably means factors that have a multiplicity of three. Thus 8 = 23 is a factor of 24 or 72 and so 2 is a cubed factor of those numbers.

Divide both terms by 24. 24(9x3 +1)

8(a + 3)

24(w + z)

24(k + 4)

24 * 24 * 24 = 13824

(s+3)(5s+8)

3(y + 4)(y + 2)

(5x + 6)(x + 4)

9 whole times, plus 3/4 of one more time.

n² - 10n + 24 = 0 You need two numbers that multiply to equal 24. They have to add to equal -10. -6 times -4 is 24 -6 plus -4 is -10 Your answer is (n - 6)(n - 4).

3 times 8 = 24

x2 + 10 - 24 = (x + 12)(x - 2)