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Q: Factor 24 cubed plus 27x squared - 8x - 9?

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9x(x2+3x-10)

the answer is (3x-2)(9x squared+6x+4)

I also need to know the answer to this problem. Can anyone answer it?

Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)

(5x - 2)(x - 5)

3x2 + 27x +60

9xy(3xy - 4)

9x2 + 27x - 36 = 9(x2 + 3x - 4) = 9(x + 4)(x - 1)

(2 - 3x)(9x^2 + 6x + 4)

3(3x + 2)(3x - 2)

Divide the entire equation by 9. (9x2 + 27x + 18)/9 would then be 9(x2 + 3x +2) The factors of this equation would be 9(x + 1)(x + 2)

19

9x

(2x - 3)(x - 12)

27x - 8 is in its simplest form.

In order to factor the sum of the cubes, we need to use this form a³ + b³ = (a + b)(a² - ab + b²). Let a³ = 27x³ and b³ = 343y³. Then, a = 3x and b = 7y. Perform substitution of these terms for the form, and we obtain: 27x3 + 343y3 = (3x + 7y)(9x2 - 21xy + 49y2)

27x2 - 90x + 27 = 9*(3x - 1)*(x - 3)

4x + 27x + 18 = 0 31x + 18= 0 31x + 18 - 18= 0 - 18 31x = -18 31x / 31 = -18 / 31 x = -.58

cube root of 27 = 3, so 3^12 = 531 441 * * * * * If the question is about 27x, rather than 27, the answer is as follows: cuberoot(27x12) = (27x)12/3 = (27x)4 = 531441x4

16x2 + 27x - 28 doesn't factor. Applying the quadratic formula, we find two real solutions:(-27 plus or minus the square root of 2521) divided by 32x = 0.725298776329149x = -2.412798776329149

Your question is ambiguous. (3x)^3 times (3x)^3 = 27x^3 times 27x^3 = 729x^6 or, if you meant 3x^3 times 3x^3 = 9x^6

27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3

You try to find two factors of -58 whose sum is -27 .You find that -29 and +2 will do it, so . . .x2 - 27x - 58 = (x - 29) (x + 2)

20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)

9 + 9y = 27x -9 -9 9y = 27x - 9 9y/9 = 27x/9 - 9/9 y = 3x -1