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a(a^2 + 1)
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How do you factor x cubed plus 3xsquaredy plus 3xy squared plus y cubed?
(x + y)(x + y)(x + y)
How do you factor y cubed plus 27z cubed?
(y + 27)(y^2 - 27y + 729)
How do you factor x cubed plus 9x squared plus 2x plus 18?
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Factor 8x cubed plus 2x squared plus 12x plus 3?
The answer is (2x^2+3)(4x+1)
How do you factor a polynomial of 4x plus 12x squared plus 16x cubed?
4x(4x^2 + 3x + 1)
Factor a cubed plus B-Cubed?
(a+b)(a squared-ab+b squared)
How do you factor 8xA cubed plus C cubed?
(2a + c)(4a2 - 2ac + c2)
How do you factor x cubed plus 3xsquaredy plus 3xy squared plus y cubed?
(x + y)(x + y)(x + y)
How do you factor x cubed plus 125?
w3+125
How do you factor y cubed plus 27z cubed?
(y + 27)(y^2 - 27y + 729)
How do you factor x cubed plus 36 x?
x(x2 + 36)
How do you factor x plus x cubed?
x(x^2 + 1)
Factor x cubed plus 5x squared plus 6x?
x(x2+5x+6)
Factor sin cubed plus cos cubed?
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
How do you factor x cubed plus 9x squared plus 2x plus 18?
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Can you factor the binomial below y cubed plus 27z cubed?
(y + 3z)(y^2 - 3yz + 9z^2)
Factor 8x cubed plus 2x squared plus 12x plus 3?
The answer is (2x^2+3)(4x+1)
