(x + 10)(x + 3)
32
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
There's a factor pair of 30 that adds up to 11. (x + 5)(x + 6)
5(6 + y)
(x + 10)(x + 3)
(x - 10)(x - 3)
32
You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).
X^2 - 13X + 30 = 0 (X-3)(X-10) easy inspection problem
Assuming you mean n2 + 11n + 30, the factors are (n + 6)(n + 5).
There's a factor pair of 30 that adds up to 11. (x + 5)(x + 6)
Dividing all terms by 4 gives: x2-x-30 = (x-6)(x+5) when factored
No.
5(6 + y)
x+11x+30(x+5)(x+6)
30+12x = 6(5+2x)