0
x3+x2+x
First, factor out the x:
x(x2+x+1)
Could stop there, but the rest is factor-able using imaginary numbers:
x(x+.5(1+i(3).5)(x+.5(1-i(3).5), where i = (-1).5, or sqrt(-1)
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
How do you factor x3 plus y3?
(x2 - xy + y2)(x + y)
How would you factor x3 plus 343?
(x + 7)(x2 - 7x + 49)
How do you factor x3?
X3 X(X2) X2(X) and, X * X * X
Factor completaly x3 plus 2x3 plus 4xplus 8?
If that's 2x2, the answer is (x + 2)(x2 + 4)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
Factor x5 plus x2?
x2(x3 + 1) is the best you can do there.
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
What is a factor of x3 plus 27y3?
x3+27y3 = (x+3y) · (x2-3xy+9y2)
Factor by grouping x3 - x2 plus 40x -40?
(x2 plus 40) (x minus 1)
Is x-2 a factor of fx equals -9 x4 plus 3 x3 - 7 x2 plus 7 x - 9?
If there is a remainder then it's not a factor otherwise yes
Is f9x0 equals x3-x2 plus 5 a linear function?
No, it is not.
Factor x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
Write a c plus plus program to find the sum of series S equals 1 plus x2 plus x3 plus x3. plus xn?
(xn+2-1)/(x2-1)
Factor x3 plus 4x2 plus x plus 4?
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
