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Q: How do you factor x squared minus 8x plus 12?

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x squared minus 12 x plus 36 = (x - 6)(x - 6)

(x + 12)(x - 3)

(x - 5)(x + 12)

(6x - 1)(6x - 1)

It is x^2 -13x +12 = (x-1)(x-12) when factored

133

The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)

x2+2x-120 = (x+12)(x-10) when factored

(n - 4)(n - 12)

x2 + x - 12 = (x + 4) (x - 3)

(x - 4)(x - 3)

(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.

3(3x + 2)(3x - 2)

It is x^2 -x -12 is (x+3)(x-4) when factored

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 37) divided by 3. c = 2.36092084343274 c = -1.694254176766073

Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========

X^2-10x-24 =(x+2)(x-12)

It is: (3x+4)(2x-3) when factored

There are no rational factors.

(2x+3)(2x+4)

-22 - 12 = -8

(x - 12)(x + 12)

Yes.

3(x - 2)(x + 2)

Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x â‰ 0.5