x2 + x - 12 = (x + 4) (x - 3)
(x - 5)(x + 12)
(x - 12)(x + 12)
(2x+3)(2x+4)
3(x + 4)(x + 1)
(x2-7x+12)/(x2-2x-3)factor the numerator & denominator:(x-4)(x-3)/(x-3)(x-1)now reduce:(x-4)(x-3)/(x+1)(x-3)(x-4)/(x+1)
(x + 12)(x - 3)
(x - 5)(x + 12)
(6x - 1)(6x - 1)
It is x^2 -13x +12 = (x-1)(x-12) when factored
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
x2+2x-120 = (x+12)(x-10) when factored
(n - 4)(n - 12)
133
(x - 4)(x - 3)
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
x^(2) - 8x + 12 Write down all the pairs of factors of '12'. They are ( 1,12) , ( 2, 6) , ( 3 ,4). Select a pair that add to '8' . Viz, ( 2,6). Set up brackets ( x 6)(x 2) Which signs???? Since '12' is positive (+), then both the signs are the same. Since '8' is negative(-), then both signs are negative. Hence ( x - 6)(x - 2) Fully factored . Done!!!!!!
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========