(x - 5)(x + 12)
(x - 12)(x + 12)
(2x+3)(2x+4)
3(x + 4)(x + 1)
(x2-7x+12)/(x2-2x-3)factor the numerator & denominator:(x-4)(x-3)/(x-3)(x-1)now reduce:(x-4)(x-3)/(x+1)(x-3)(x-4)/(x+1)
(x + 12)(x - 3)
(x - 5)(x + 12)
(6x - 1)(6x - 1)
It is x^2 -13x +12 = (x-1)(x-12) when factored
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
x2+2x-120 = (x+12)(x-10) when factored
133
(n - 4)(n - 12)
(x - 4)(x - 3)
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
Find out what two numbers add up to -8 yet when mutiplied they produce 12 and so: x squared-8x+12 = (x-2)(x-6) when factored
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========