6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
The square root of 16n to the power of two, (√16n)2 is just simply 16n. Any number or monomial that is squared after the square root is taken is just the number itself, since squaring is the inverse property of taking the square root of something.
cannot be simplified, unless there's an = you're leaving out.
16n
Let the numbers be 'm' & 'n' Hence mn = 51 (Multiplication) m + n = -16 (Addition) Algebraically rearrange m = -16 -n Ssubstitute (-16-n) n = 51 -16n - n^2 = 51 n^(2) + 16n + 51 = 0 ( It is now in Quadratic form to solve). Complete the Square (n + 8)^2 - 8^(2) = -51 (n + 8)^2 = -51 + 64 = 13 Square root both sides n + 8 = +/-sqrt(13) n + 8 = +/- 3.60555.... n = -13.60555.... & -4.39444.... Are the two number.
6n2 + 16n can be factorised to give 2n(3n + 8) so the highest factor is 2n.
(4x-5)(4x+5)
2n(3n + 8)
Look at the coefficients. -16 - 14 = -30. Therefore, -16n - 14n = -30n.
you cant factor this any more
16n
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
It is: 16n
The square root of 16n to the power of two, (√16n)2 is just simply 16n. Any number or monomial that is squared after the square root is taken is just the number itself, since squaring is the inverse property of taking the square root of something.
The GCF is 4n
[ 13n + 25 ] is.
(8n)4(16n)2= (84n4)(162n2)=(82 x 162)(n4 x n2)= 1,048,576n4+2= 1,048,576n6