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Q: What is 3c plus 11c?

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It is 7 - 8c.

6c2 -11c + 3 factors are (3c - 1)(2c - 3)

11c + 22c + 12 = 33c + 12 = 3(11c + 4) = 3 x (11c + 4)

100 = 56 + 11c 44 = 11c 4 = c

3c-d

4c+2 = 3c+9 4c-3c = 9-2 c = 7

6c.

3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4

12

9c is.

4a + 3c - 2b - c + a - b = 5a - 3b + 2c

The like terms are sums of b terms and c terms separately 5c+2c+3c+4b 5c +2c + 4b + 3c => 10c + 4b

3c

17-3= 4c+3c c=2

That's not even a question. It's only a statement that says that some number is equal to itself.

The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7

sdfsdfs

4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2

It is 3 + 54c.

-((3c - 4)(3c + 4)(2c - 5)(2c + 5))

That factors to (b + 3)(a + c)

12bc - 4bd - 15xc + 5xd = 4b(3c - d) - 5x(3c - d) = (3c - d)(4b - 5x)

(12c5 - 18c3 + 9c) / (-3c) = -4c4 + 6c2 - 3

2ab - 6ac + 3b - 9c = 2a(b - 3c) + 3(b - 3c) = (2a + 3)(b - 3c).

2b+3c