Best Answer

2a + 4b + 8c = 2(a + 2b + 4c)

You could also continue by factoring the inside of the parentheses a bit:

2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])

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โˆ™ 2012-04-16 23:08:05
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โˆ™ 2020-08-17 13:53:37



6(a + b)+8(c)

14(a + b + c)

It is because ''a ,b ,c'' cannot be added, divided and subtracted

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Q: How do you factorise 2a plus 4b plus 8c?
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