They both share the same tangent ratio so let the height of the monument be x:
500/x = 40/36
Solving the above equation gives x a value of 450 which is the height in feet.
Ten is to two as 40 is to x, yielding: 200ft.
Using trigonometry its height is 12 feet
5
The height of the flagpolle is 26.25 feet
pyramid
The flagpole is 15.92 metres, approx.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
Using trigonometry its height is 12 feet
5
If you also know its shadow then you can work out the angle of elevation
The height of the flagpolle is 26.25 feet
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
pyramid
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
56 feet.
84 feet tall