5
84 feet tall
Ten is to two as 40 is to x, yielding: 200ft.
circumscribed
Circumscribing.
5
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Rectangle
The flagpole is 15.92 metres, approx.
84 feet tall
Ten is to two as 40 is to x, yielding: 200ft.
circumscribed
Circumscribing.
It works out as: 42.353 feet tall rounded to 3 decimal places
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
21 ft how is the equation to give you this result
The positioning of the sun throughout the day.