They both share the same tangent ratio so let the height of the monument be x:
500/x = 40/36
Solving the above equation gives x a value of 450 which is the height in feet.
Ten is to two as 40 is to x, yielding: 200ft.
Using trigonometry its height is 12 feet
5
The height of the flagpolle is 26.25 feet
pyramid
The flagpole is 15.92 metres, approx.
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
Ten is to two as 40 is to x, yielding: 200ft.
Using trigonometry its height is 12 feet
5
If you also know its shadow then you can work out the angle of elevation
The height of the flagpolle is 26.25 feet
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
pyramid
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
To solve this problem, we can set up a proportion using the similar triangles formed by the flagpole and its shadow, and the mailbox and its shadow. The height of the flagpole to its shadow is 30 feet to 12 feet, which simplifies to 5:2. Using this ratio, we can determine the height of the mailbox by setting up the proportion 5/2 = x/1.5 (converting 18 inches to feet). Solving for x, the height of the mailbox would be 3.75 feet.
84 feet tall