704
To find the height of the box, you first need to determine the dimensions of the base. Since the area of the base is 32 square centimetres, you can find the side lengths by taking the square root of 32, which is approximately 5.66 cm. Next, you can calculate the height by dividing the volume of the box (96 cubic centimetres) by the area of the base (32 square centimetres), resulting in a height of 3 cm.
(length x width) x height=volume find the area of the base then multiply that by the height.
Multiply the base*height*width.
The height is irrelevant to the area of the base, which is (8 inches)(3.5 inches) or 28 square inches.
Lateral Area= p times h p= perimeter of the base h=height of the figure Surface Area= Lateral Area + 2 times (B) B= Area of base
It is 3 cm high.
30. It's the Base Area times the height.
I think you mean the volume. It is the base x height x length.
To find the volume of the box, you can use the formula for volume: ( \text{Volume} = \text{Base Area} \times \text{Height} ). Given that the height is 5 cm and the area of the lid (which is the base area) is 9 cm², the volume is calculated as ( 9 , \text{cm}^2 \times 5 , \text{cm} = 45 , \text{cm}^3 ). Therefore, the volume of the box is 45 cm³.
96cm3/ 32cm2 = 3cm
Area of triangular cross-section = 0.5*3*4.5 cm2 Volume of box = Cross sectiona area*height = 0.5*3*4.5*25 cm3 = 168.75 cm3
base times height