Use the Law of Cosines: c^2 = a^2+b^2-2ab cos C. Here, the two legs of a triangle are both the radius (14 inches long), and the angle between them is 35 degrees. So c^2 = 14^2+14^2-2*14*14*cos 35 c^2 = 2*14^2(1-cos 35) c^2 = 70.89.. c = 8.42..
Then the radius bisects the chord.
No, but the diameter of a circle is its largest chord
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
a chord is a line between two points on the circle the radius is a line from the center to the circle
No, a radius connects the center of a circle the a point on the outside, a chord connects to points on the outside of the circle. Thanks for asking on
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
Half of the chord, the distance of the midpoint from the center, and a radius, form a right triangle, with the radius as its hypotenuse. (4.5)2 + (6)2 = (radius)2 (20.25) + (36) = 56.25 = R2 Radius = 7.5 inches
Then the radius bisects the chord.
No, but the diameter of a circle is its largest chord
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
A chord is when two points in a circle are connected by segment. A diameter is a chord, but not a radius. The radius is not a complete segment in the circle
The relationship between the chord and the radius of the circle is Length of the chord = 2r sin(c/2) where r = radius of the circle and c = angle subtended at the center by the chord
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Bisects
Perpendicular.
a chord is a line between two points on the circle the radius is a line from the center to the circle
No, a radius connects the center of a circle the a point on the outside, a chord connects to points on the outside of the circle. Thanks for asking on