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Bisects

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Q: If a radius of a circle is perpendicular to a chord then it that chord?
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If a radius of a circle is perpendicular to a chord then?

Then the radius bisects the chord.


If a radius of a circle is perpendicular to a chord at what point does it intersect the chord?

The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.


If a radius of a circle intersects a chord then it bisects that chord?

If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.


If a radius of a circle bisects a chord then it is to that chord?

Perpendicular.


A radius of a circle is perpendicular to a chord if and only if?

Bisects that chord


If a radius of a circle intersects a chord it is perpendicular to that chord?

False


What is a line perpendicular to a radius of a circle called?

A Chord. Or another radius!


If a radius of a circle is perpendicular to a chord then it bisects that chord?

YesAt a right angle


True or False If a radius of a circle intersects a chord it is perpendicular to that chord?

its false


True or False if a radius of a circle is perpendicular to a chord then it bisects that chord?

true, because both distances of the chord are congruent


How do you find the radius of a circle if you know the length of a chord and the shortest distance from the center of the chord to the circle?

Imagine if you will a circle with a chord drawn through it and a line running from the center of that chord to the center of the circle. That line is necessarily perpendicular to the chord. This means you have a right triangle whose hypotenuse is the radius of the circle. The radius is thus given by: r = sqrt{(1/2 chord length)^2 + (length of perpendicular line)^2} The actual formula to find the radius is as follows: r= C squared/8a + a/2, where C is the chord length, and a is the distance from center point of the chord to the circle , and a and C form an angle of 90 degrees. the entire formula before simplification is r = sqrt {(1/2 C)^2 + (r-a)^2}


Is a radius a chord of a circle?

No, but the diameter of a circle is its largest chord